Q&R Statistics - Normal Distribution: z to Proportion

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Q&R Statistics - Normal Distribution: z to Proportion

Postby bradley » Sat Mar 07, 2009 9:56 pm

Normal Dist, z to p

Calculates proportions of the normal distribution based on z.


Variables

z = 0.412
Minimum value = -6.000000
Maximum value = 6.000000
Display to 3 decimal places

The number of std deviations from the mean of the std normal distribution with mean = 0 and std deviation = 1. Use positive numbers for z. Example: 0.412


Results

Cum if z neg = 0.340170
Display to 6 decimal places
Formula = 1-normsdist(z)

The cumulative proportion of the std normal distribution if z is negative. This is also the proportion of the std normal distribution that is not captured if z is positive. Example: 0.340170

Cum if z pos = 0.659830
Display to 6 decimal places
Formula = normsdist(z)

The cumulative proportion of the std normal distribution if z is positive. This is also the proportion of the std normal distribution that is not captured if z is negative. Example: 0.659830

Mean to z = 0.159830
Display to 6 decimal places
Formula = normsdist(z)-0.5

The 1-sided proportion from the mean to z. Example: 0159830

Mean ± z = 0.319660
Display to 6 decimal places
Formula = 2*(normsdist(z)-0.5)

The 2-sided proportion of the std normal distribution captured by the mean ± z. Example: 0.319660

Out on 1 side = 0.340170
Display to 6 decimal places
Formula = (1-(2*(normsdist(z)-0.5)))/2

The proportion of the std normal distribution outside of one side of the mean ± z. This is equivalent to "Cum neg z", but can be on either side of the distribution. Example: 0.340170

Out on 2 sides = 0.680340
Display to 6 decimal places
Formula = 1-(2*(normsdist(z)-0.5))

The 2-sided proportion of the std normal distribution outside of the mean ± z. Example: 0.680340


Notes

Calculates proportions (i.e., probabilities) using the standard normal variable (z) of the standard normal distribution with mean = 0 and std deviation = 1.

ENTER z AS A POSITIVE NUMBER.
bradley
 
Posts: 7
Joined: Wed Mar 04, 2009 5:57 am

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